This quarter I am teaching undergraduate differential geometry at UC Irvine. We are spending two quarters on this course, which is slightly longer than a semester course, such as the one I TAed at Princeton. So we have more time to study various topics which I didn’t know when I was in college.
We are using the book “Elements of Differential Geometry” by Richard S. Millman and George D. Parker, different from the more popular do Carmo’s “Differential Geometry of Curves and surfaces“. Indeed do Carmo’s was once regarded as an “easy” book in some sense. Indeed the core materials won’t differ too much but details vary.
So the purpose of writing (maybe several) posts is to clarify some understanding of about materials of the book/course, and to fill some gaps existing in many places in the book. Hopefully this can attract my students occasionally.
In the first post of this series, we consider the rotation index theorem in plane curve theory.
Basic notations
Definition. A regular plane curve is a
-map
such that
for all
. It is a unit speed curve if
for all
.
Now we consider only unit speed curves. In fact all regualr curves can be reparametrized to be a unit speed curve.
Definition: The tangent vector field is the vector-valued
-map
. The normal vector field
is basically “i” times
, where i is the imaginary unit. The curvature is then the
-function
.
Now we consider closed curves, which are equivalent to a periodic map
. If
is of unit speed, then the least positive period is equal to the perimeter, usually denoted by
, of the curve. A closed curve is simple, if
implies that
.
Rotation index
Now it is a bit cumbersome to define the notion of rotation index. Basically, it counts within one period, how many 360 degrees you have turned.
Indeed, if you know some topology, the rotation index can be defined as follows. The tangent vector field
defines a periodic map to the unit circle of
. So if we glue 0 and L to get a circle of perimeter L, then
induces a continuous map between two circles. The rotation index is the topological degree of this map.
If you know something about differential forms, then on the unit circle (which is the target space of the map
), there is a differential 1-form, called
. We can integrate this 1-form on the 1-dimensional circle, and we have
which agrees with our convention that the perimeter of a unit circle is
. Now the pull-back of
by the map
is a 1-form on
, which is actually equal to
, where
is the curvature. The rotation index is then defined to be
.
However, in the textbook, if we don’t want to introduce the language of topological degree or differential forms, then we have to define a function
along the curve, which is difficult to give a concise expression.
Rotation index theorem
Anyway, the main theorem, called rotation index theorem is
“If
is a simple closed plane curve, then its rotation index is either 1 or -1.”
The proof given in the textbook was due to Heinz Hopf. I think a key point here is to make use of the condition that the curve is simple.
Indeed, we can define a vector valued function
for
. If
, then
is equal to the unit vector pointing to the direction of
. That is
.
We define
, the tangent vector at
. And we notices that
. If we write down the expression of
using coordinates, then we can see that
is a
-map. And only for simple curves this map is well-defined.
Now, the differential form
on
is pull-backed to a 1-form on the domain of
, which is a triangle with three sides
. Here

We can orient the boundar so that it goes in the counterclockwise direction.
By our “fancy” definition of rotation index, we see that the rotation index is equal to the integral of this 1-form on the diagonal
. However, by the great “Stokes-Green” formula, we can reduce this integral to the integral of the 1-form on the other two sides of the triangle, plus the contribution of the interior of the triangle. However, the form
is closed, which means the pull-backed 1-form is also closed. This means the contribution from the interior is zero.
On the other hand, if we choose good starting point of the simple closed curve, it is easy to see that the integral of the 1-form on the other two sides-one horizontal and one vertical-are either both
or both
. Therefore the rotation index should be either 1 or -1.
On the other hand, thinking a little bit more, if you know that the topological degree is homotopy invariant, then the triangle also gives a concrete homotopy which relates the rotation index to the topological degree of another continuous map.
(New update: I am supposed to give a undergraduate MathClub talk in a few days. Originally I would like to discuss Morse theory. But now I feel that differential forms is a good topic and I can include this as an example.)
0.000000
0.000000